Question:

The standard emf of a cell (in V) involving the reaction, 

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Standard electrode potentials are used to calculate the standard emf of the overall reaction in a galvanic cell.
Updated On: Dec 11, 2025
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Correct Answer: 0.49

Solution and Explanation

Step 1: Understanding the reaction.
The given reaction is: \[ 2 \text{Ag}^+ (aq) \rightarrow \text{Ag} (s) + \text{Ag}^{2+} (aq) \] The standard electrode potentials are: \[ \text{Ag}^+ (aq) + e^- \rightarrow \text{Ag} (s), E^o = 0.62 \, \text{V} \] and \[ \text{Ag}^{2+} (aq) + e^- \rightarrow \text{Ag}^+ (aq), E^o = 0.12 \, \text{V} \] Step 2: Calculating the standard emf.
The standard emf for the reaction is: \[ E^o = E^o (\text{cathode}) - E^o (\text{anode}) \] Here, \( \text{Ag}^+ \) is reduced (cathode) and \( \text{Ag}^{2+} \) is oxidized (anode). So: \[ E^o = 0.62 - 0.12 = 0.50 \, \text{V} \] Step 3: Conclusion.
The standard emf of the cell is 0.50 V.
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