Step 1: Fertilizer requirement per hectare.
Application = 200 kg/ha = 200,000 g/ha
Step 2: Fertilizer delivered per revolution of metering wheel.
One revolution delivers 38 g per row.
Row spacing = 40 cm → 1 ha has \(10000 / 0.40 = 25000\) row-meters.
Step 3: Total revolutions needed.
Total revolutions = 200000 / 38 = 5263.16
Step 4: Ground wheel circumference (D=60 cm).
\[
C = \pi D = 3.14 \times 0.60 = 1.884\ \text{m}
\]
Total distance = 25000 m.
Ground wheel revolutions = 25000 / 1.884 = 13271.7
Step 5: Speed ratio.
\[
\text{Speed ratio} = \frac{\text{Ground wheel rev}}{\text{Metering wheel rev}} = \frac{13271.7}{5263.16} = 2.52
\]
Final Answer: (B) 2.52 : 1
| List-I (Fertilizer) | List-II (Component/Description) |
|---|---|
| (A) SSP | (I) Sulphur |
| (B) MoP | (II) KCl |
| (C) Urea | (III) Organic chemical fertilizer |
| (D) CAN | (IV) Neutral fertilizer |
Consider the relationships among P, Q, R, S, and T:
• P is the brother of Q.
• S is the daughter of Q.
• T is the sister of S.
• R is the mother of Q.
The following statements are made based on the relationships given above.
(1) R is the grandmother of S.
(2) P is the uncle of S and T.
(3) R has only one son.
(4) Q has only one daughter.
Which one of the following options is correct?