The area of an image is inversely proportional to the square of the spatial resolution. Since the spatial resolution of image \( P \) is 80 m and that of image \( Q \) is 20 m, the ratio of the areas of the two images will be:
\[
\left(\frac{80}{20}\right)^2 = 4^2 = 16.
\]
Thus, image \( P \) will cover sixteen times the area of image \( Q \), making option (B) correct.
Since the resolution of image \( P \) is lower (80 m) compared to \( Q \) (20 m), the minor details will be clearer in image \( Q \), making option (C) correct.
Step 1: Conclusion
- Image \( P \) will cover 16 times the area of image \( Q \), so option (B) is correct.
- Image \( Q \) has a higher resolution, so minor details will be clearer in \( Q \), making option (C) correct.