a. Positive :
In the given case, force and displacement are in the same direction.
Hence, the sign of work done is positive. In this case, the work is done on the bucket.
b. Negative :
In the given case, the direction of force (vertically downward) and displacement (vertically upward) are opposite to each other.
Hence, the sign of work done is negative.
c. Negative :
Since the direction of frictional force is opposite to the direction of motion, the work done by frictional force is negative in this case.
d. Positive :
Here the body is moving on a rough horizontal plane. Frictional force opposes the motion of the body.
Therefore, in order to maintain a uniform velocity, a uniform force must be applied to the body. Since the applied force acts in the direction of motion of the body, the work done is positive.
e. Negative :
The resistive force of air acts in the direction opposite to the direction of motion of the pendulum. Hence, the work done is negative in this case.
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.
W = Force × Distance
Where,
Work (W) is equal to the force (f) time the distance.
W = F d Cos θ
Where,
W = Amount of work, F = Vector of force, D = Magnitude of displacement, and θ = Angle between the vector of force and vector of displacement.
The SI unit for the work is the joule (J), and it is defined as the work done by a force of 1 Newton in moving an object for a distance of one unit meter in the direction of the force.
Work formula is used to measure the amount of work done, force, or displacement in any maths or real-life problem. It is written as in Newton meter or Nm.