Assume the sides of rectangular field be \(3x\) and \(4x\) m
Area of rectangle = \(l × b\) = 7500
= \(3x × 4x = 7500\)
\(x^2 = \frac{7500}{12}\) = 625
\(x = \sqrt{625}\)
\(x = 25\)
> Perimeter of field = 2(\(3x + 4x\)) = \(14x\)
Here \(x = 25\), so,
14 × 25 = 350 \(m\)
The Cost of fencing = 350 × 0.25 = \(Rs.\) 87.50\(\)
The correct option is (A): 87.50