
Step 1: Understanding the Question
The problem asks us to determine how many of the 2D shapes in Set K will result in a 3D solid with more than 8 surfaces when extruded along the Z-axis.
Step 2: Key Formula or Approach
When a 2D polygon with \(n\) sides is extruded, it forms a 3D solid. The total number of surfaces of this solid is given by the formula:
\[ \text{Total Surfaces} = 2 + n \] Here, '2' represents the front and back faces (which are the original 2D shape), and '\(n\)' represents the number of side surfaces, with one side surface corresponding to each edge of the original 2D shape.
The condition is that the number of surfaces must be greater than 8:
\[ 2 + n>8 \] \[ n>6 \] So, we need to count how many shapes in Set K have more than 6 sides (or edges).
Step 3: Detailed Explanation
Let's count the number of sides for each shape in Set K:
1. Plus sign (+): By tracing the perimeter, we can count the number of straight edges. It has 12 sides.
- Surfaces = 2 + 12 = 14. Since 14 $>$ 8, this shape qualifies.
2. Shape J: Counting the straight edges around the perimeter gives 8 sides.
- Surfaces = 2 + 8 = 10. Since 10 $>$ 8, this shape qualifies.
3. Shape V: This shape is a simple polygon with 6 sides.
- Surfaces = 2 + 6 = 8. The condition is ""more than 8 surfaces"", so 8 does not qualify.
4. Shape K: Counting the sides along its perimeter gives 12 sides.
- Surfaces = 2 + 12 = 14. Since 14 $>$ 8, this shape qualifies.
5. Semicircle with rectangle: This shape has 3 straight sides and 1 curved side. In the context of extrusion, each of these forms a surface. So, we can consider \(n=4\).
- Surfaces = 2 (front/back) + 3 (flat sides) + 1 (curved side) = 6. Since 6 is not greater than 8, this shape does not qualify.
Step 4: Final Answer
The shapes that will have more than 8 surfaces when extruded are the plus sign (+), shape J, and shape K.
There are a total of 3 such shapes.
Therefore, the correct option is (B).



