We use the formula for resistance: \(R = ρ × (\frac L A)\)
Rearranging to solve for resistivity (ρ): \(ρ = R × (\frac AL)\)
Given:
\(R = 1 Ω\),
\(L = 1 m,\)
\(A = 1\ mm² = 1 × 10⁻⁶ \ m²\)
Substitute the values: \(ρ = 1 × (\frac {1 × 10⁻⁶}{1}) = 1 × 10⁻⁶\ Ω·m\)
The correct option is (B): \(10^-6\ Ω-m\)