Question

The resistance of a wire is 500 \(\Omega\). Its electrical conductivity will be:

• A. \(0.002 \, \Omega^{-1}\)
• B. \(0.02 \, \Omega\)
• C. \(50 \, \Omega^{-1}\)
• D. \(500 \, \Omega^{-1}\)

Hint:

Conductivity is the inverse of resistance: \[ \sigma = \frac{1}{R}. \]

Answer 1

The Correct Option is A

Electrical conductivity \( \sigma \) is defined as the reciprocal of resistance \( R \): \[ \sigma = \frac{1}{R}. \] Given the resistance: \[ R = 500 \, \Omega, \] we calculate the conductivity as: \[ \sigma = \frac{1}{500} = 0.002 \, \Omega^{-1}. \] This means the material has a conductivity of \( 0.002 \, \text{siemens} \) (since \( \Omega^{-1} \) is equivalent to siemens), indicating how easily electric current can flow through it.