Question:

The reduced form of the Boolean function \( F = xyz + xyz' + x'yz + zy'z \) is

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Use the identity \( x + x' = 1 \) and \( y + y' = 1 \) to simplify Boolean expressions efficiently.
Updated On: Oct 7, 2025
  • \( xy + yz + xz \)
  • \( x + yz + xz \)
  • \( x + y + z \)
  • \( xy + yz + xz \)
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The Correct Option is D

Solution and Explanation

Let's simplify the Boolean expression step by step: \[ F = xyz + xyz' + x'yz + zy'z \] We can factor terms: \[ F = xz(y + y') + yz(x' + x) \] Using the identity \( y + y' = 1 \) and \( x + x' = 1 \), we get: \[ F = xz(1) + yz(1) \] \[ F = xz + yz \] Thus, the reduced form of the Boolean function is \( \boxed{xy + yz + xz} \).
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