Question:

The ratio of radii to the gravitational acceleration of planets X and Y are R and a respectively. The ratio of escape velocities at them, is

Updated On: Jun 21, 2022
  • $ \sqrt{aR} $
  • $ \frac{1}{\sqrt{aR}} $
  • $ aR $
  • $ \frac{1}{aR} $
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The Correct Option is A

Solution and Explanation

$ {{v}_{e}}\propto \sqrt{gR} $ Given $ \frac{{{R}_{1}}}{{{R}_{2}}}=R $ and $ \frac{{{g}_{1}}}{{{g}_{2}}}=a $ $ \therefore $ $ \frac{{{({{v}_{e}})}_{x}}}{{{({{v}_{e}})}_{y}}}=\sqrt{\frac{{{g}_{1}}{{h}_{1}}}{{{g}_{2}}{{h}_{2}}}}=\sqrt{aR} $
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Concepts Used:

Gravitational Potential Energy

The work which a body needs to do, against the force of gravity, in order to bring that body into a particular space is called Gravitational potential energy. The stored is the result of the gravitational attraction of the Earth for the object. The GPE of the massive ball of a demolition machine depends on two variables - the mass of the ball and the height to which it is raised. There is a direct relation between GPE and the mass of an object. More massive objects have greater GPE. Also, there is a direct relation between GPE and the height of an object. The higher that an object is elevated, the greater the GPE. The relationship is expressed in the following manner:

PEgrav = mass x g x height

PEgrav = m x g x h

Where,

m is the mass of the object,

h is the height of the object

g is the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.