Question

The ratio of is given as \( \frac{E{\lambda}_1 b_2}{E{\lambda}_1 b_1} \) is given as:

• A. \( \left(\frac{T_2}{T_1}\right)^5 \)
• B. \( \left(\frac{T_2}{T_1}\right)^4 \)
• C. \( \left(\frac{T_2}{T_1}\right)^3 \)
• D. \( \left(\frac{T_2}{T_1}\right)^2 \)

Hint:

When dealing with thermal ratios, the relationship between temperature and thermal properties often involves powers of the temperature ratio.

Answer 1

The Correct Option is B

Step 1: Analyze the given ratio.
The ratio \( \frac{E{\lambda}_1 b_2}{E{\lambda}_1 b_1} \) is a function of temperature ratio \( \frac{T_2}{T_1} \), and it typically corresponds to a specific heat or thermal conductivity ratio. Step 2: Conclusion.
This ratio is given by \( \left( \frac{T_2}{T_1} \right)^4 \), which is derived from the laws of thermodynamics. Final Answer: \[ \boxed{\left( \frac{T_2}{T_1} \right)^4} \]