Question:
The ratio of escape velocity and orbital velocity of satellite revolving near the earth:
The ratio of escape velocity and orbital velocity of satellite revolving near the earth:
Updated On: Jul 28, 2022
- $ \sqrt{2} $
- 2
- 3
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The Correct Option is A
Solution and Explanation
$v_{e}=\sqrt{2} v_{o} \,\,$
$ v_{e}=$ escape velocity
$ \frac{v_{e}}{v_{o}}=\sqrt{2} \,\,$
$ v_{0}=$ orbital velocity
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].