Question:

The rate constant of a first-order reaction is \( 2 \times 10^{-3} \, \text{s}^{-1} \). What is the half-life of the reaction?

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For first-order reactions, the half-life is independent of the initial concentration, unlike zero-order and second-order reactions.
Updated On: Apr 15, 2025
  • 0.347 s
  • 1.4 s
  • 0.693 s
  • 2.0 s
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The Correct Option is A

Solution and Explanation

For a first-order reaction, the half-life is given by the equation: \[ t_{\frac{1}{2}} = \frac{0.693}{k} \] Where: - \( k = 2 \times 10^{-3} \, \text{s}^{-1} \) is the rate constant. Substitute the values: \[ t_{\frac{1}{2}} = \frac{0.693}{2 \times 10^{-3}} = 346.5 \, \text{s} \] Thus, the half-life of the reaction is approximately 0.347 s.
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