Question:

The question below has two statements, I and Impark your answer as
For a differential expression
I. d/dx (sin2(3x)) = 2 cos (3x)
II. d/dx (au) = au (log a) du/dx

Updated On: Sep 25, 2024
  • Statement I is True, but not the other one.
  • Statement II is True, but not the other one.
  • Both the statements are True.
  • Neither of the statements is True.
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The Correct Option is B

Solution and Explanation

I. ddx(sin2(3x))=2sin(3x)×3=6sin(3x)\frac{d}{dx} \left( \sin^2(3x) \right) = 2\sin(3x) \times 3 = 6\sin(3x)
In this case, The equation 1 is not True.
II. ddx(au)=au(loga)dudx\frac{d}{dx} \left( a^u \right) = a^u (\log a)^{\frac{du}{dx}}
In this case, equation 2 is True
The correct option is (B)
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