Question:
The question below has two statements, I and Impark your answer as
For an equation ax2 + bx + c = 0, its roots are
I. Real and different if b2 \(>\) 4ac.
II. Imaginary and equal if b² \(<\) 4ac.
The question below has two statements, I and Impark your answer as
For an equation ax2 + bx + c = 0, its roots are
I. Real and different if b2 \(>\) 4ac.
II. Imaginary and equal if b² \(<\) 4ac.
For an equation ax2 + bx + c = 0, its roots are
I. Real and different if b2 \(>\) 4ac.
II. Imaginary and equal if b² \(<\) 4ac.
Updated On: Sep 25, 2024
- Statement I is True, but not the other one.
- Statement II is True, but not the other one.
- Both the statements are True.
- Neither of the statements is True.
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The Correct Option is A
Solution and Explanation
For an equation \(ax^2 + bx + c = 0\)
the roots are = \(\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Now, if \(b^2\) > \(4ac\), roots are real and different.
\(b^2\) = \(4ac\), roots are equal.
If \(b^2\) < 4ac, This is case II in which the roots are equal.
so, Case II is incorrect.
The correct option is (A)
the roots are = \(\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Now, if \(b^2\) > \(4ac\), roots are real and different.
\(b^2\) = \(4ac\), roots are equal.
If \(b^2\) < 4ac, This is case II in which the roots are equal.
so, Case II is incorrect.
The correct option is (A)
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