Question:
The purple colour of ${KMnO4}$ is due to the transition
The purple colour of ${KMnO4}$ is due to the transition
Updated On: Apr 15, 2024
- $C.T. (L \to M)$
- $C.T. (M \to L)$
- $d-d$
- $p-d$
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The Correct Option is A
Solution and Explanation
The permanganate ion has an intense purple colour. Mn (+ VII) has a $d^0$ configuration. So the colour arises from charge transfer and not from d?d spectra.
In ${MnO4^{-}}$ an electron is momentarily changing ${O^{- -}}$ to ${O^{-}}$ and reducing the oxidation state of the metal from Mn(VII) to Mn (VI). Charge transfer requires that the energy levels on the two different atoms are fairly close.
$O = (8) = 2_K , 6_L$
$Mn (25) = 2_K , 8_L , 15_M$
hence the charge transfer occurs from $L \to M $
In ${MnO4^{-}}$ an electron is momentarily changing ${O^{- -}}$ to ${O^{-}}$ and reducing the oxidation state of the metal from Mn(VII) to Mn (VI). Charge transfer requires that the energy levels on the two different atoms are fairly close.
$O = (8) = 2_K , 6_L$
$Mn (25) = 2_K , 8_L , 15_M$
hence the charge transfer occurs from $L \to M $
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Lanthanoids
Lanthanoids are at the top of these two-row, while actinoids are at the bottom row.
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