Let's analyze the reaction step by step:
The starting compound is benzyl chloride (C₆H₅CH₂Cl), which contains a benzyl group (C₆H₅CH₂-) attached to a chlorine atom.
The reaction with alcoholic NH₃ (ammonia) leads to a nucleophilic substitution where ammonia replaces the chlorine atom to form benzylamine (C₆H₅CH₂NH₂). This is the product A.
In the second step, the reaction with excess CH₃Cl (methyl chloride) results in the methylation of the amine group, leading to N, N-dimethylphenylmethanamine (C₆H₅CH₂NH(CH₃)₂). This is the product B.
The correct answer is (A) : N, N-Dimethyl phenyl methanamine.
Match List - I with List - II:
Choose the correct answer from the given below options
IUPAC names of the following compounds A and B are: