Question:

The pressure-volume work for an ideal gas can be calculated by using the expression $W = - \int\limits^{V_{f}}_{V_i} P_{ex} \,dV$. The work can also be calculated from the $PV -$ plot by using the area under the curve within the specified limits. When an ideal gas is compressed $(i)$ reversibly or $(ii)$ irreversibly from volume $V_i$ to $V_f$. Choose the correct option.

Updated On: Jul 7, 2022
  • $W_{reversible} = W_{irreversible}$
  • $W_{reversible} > W_{irreversible}$
  • $W_{reversible} < W_{irreversible}$
  • $W_{reversible} = W_{irreversible} + P_{ex} \Delta \,V$
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The Correct Option is B

Solution and Explanation

In both the curves, work done on the gas is represented by the shaded area and the area under the curve is always more in irreversible compression. Hence, $W_{irreversible} > W_{reversible} $
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Notes on Partial pressure

Concepts Used:

Partial Pressure

Partial Pressure is defined as if a container filled with more than one gas, each gas exerts pressure. The pressure of anyone gas within the container is called its partial pressure.

Dalton’s Law of Partial Pressure:

According to Dalton’s law of partial pressures, the total pressure exerted by the mixture of gases is the sum of the partial pressure of every existing individual gas, and every gas is assumed to be an Ideal gas.

Ptotal = P1 + P2 + P3

Where P1, P2, P3 are the partial pressures of gas 1, gas 2, and gas 3. Since every gas has an independent behavior, the ideal gas law is used to find the pressure of that gas if its number of moles, the volume of container and temperature is known.