Question:
The power obtained in a reactor using $U^{235}$ disintegration is $1000\, {kW}$. The mass decay of $U^{235}$ per hour is
The power obtained in a reactor using $U^{235}$ disintegration is $1000\, {kW}$. The mass decay of $U^{235}$ per hour is
Updated On: Jul 8, 2024
- 10 microgram
- 20 microgram
- 40 microgram
- 1 microgram
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The Correct Option is C
Solution and Explanation
$E = Pt = mc ^{2}$
$m =\frac{ Pt }{ c ^{2}}=\frac{10^{6} \times 3600}{\left(3 \times 10^{8}\right)^{2}}$
$m =40 \,\mu gm$
$m =\frac{ Pt }{ c ^{2}}=\frac{10^{6} \times 3600}{\left(3 \times 10^{8}\right)^{2}}$
$m =40 \,\mu gm$
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Concepts Used:
Decay Rate
The disintegration of unstable heavy atomic nuclei into lighter, more stable, atomic nuclei, accompanied in the process by the emission of ionizing radiation (alpha particles, beta particles or gamma rays). This is a random process at the atomic level but, given a large number of similar atoms, the decay rate on average is predictable, and is usually measured by the half-life of the substance.
The equation for finding out the decay rate is given below:
