Potential energy refers to the energy possessed by an object due to its position
The correct answer is Option B) by the system against a conservative force
Potential energy will increase when work is done by the system against a conservative force.
-U = Wconservative force
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The correct answer is Option B) by the system against a conservative force
When you lift a weight, you are doing work against the force of gravity. This work increases the potential energy of the weight, which is stored as gravitational potential energy.
1) When a spring is streched, you are doing work against the elastic force of the spring. This work increases the potential energy of the spring, which is stored as elastic potential energy.
2) While charging a battery, you are doing work against the electrostatic force of the electrons. This work increases the potential energy of the electrons, which is stored as electrical potential energy.
In all of these cases, the work done by the system against a conservative force increases the potential energy of the system. This potential energy can then be converted into other forms of energy, such as kinetic energy, heat, or light.
- The potential energy of the person increases as they climb the hill, because they are doing work against the force of gravity.
- The potential energy of the ball decreases as it rolls down the hill, because the work done by gravity is converted into kinetic energy.
In all of these cases, the potential energy of the system increases or decreases depending on whether the work done by the system is against or with the conservative force.
The correct answer is Option B) by the system against a conservative force
Potential energy refers to the energy possessed by an object due to its position. The relationship between potential energy and work is influenced by the presence of conservative forces.
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The current passing through the battery in the given circuit, is:
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A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
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