Question:

The positive charged ball is suspended by thread of silk. If we place a positive charge $ {{q}_{0}} $ at one point and measure the $ F/{{q}_{0}}, $ then this can say that electric field E

Updated On: Jun 21, 2022
  • $ >\frac{F}{{{q}_{0}}} $
  • $ =\frac{F}{{{q}_{0}}} $
  • $ =\frac{F}{{{q}_{0}}} $
  • $ Can't\,be\,measured $
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The Correct Option is A

Solution and Explanation

Electric field, $ E>\frac{F}{{{q}_{0}}} $
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Concepts Used:

Electric Field

Electric Field is the electric force experienced by a unit charge. 

The electric force is calculated using the coulomb's law, whose formula is:

\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)

While substituting q2 as 1, electric field becomes:

 \(E=k\dfrac{|q_{1}|}{r^{2}}\)

SI unit of Electric Field is V/m (Volt per meter).