Question:
The position vector of $A$ and $B$ are $ 2\hat{i}+2\hat{j}+\hat{k}$ and $2\hat{i}+4\hat{j}+4\hat{k}$
The length of the internal bisector of $?BOA$ triangle $AOB$ is
The position vector of $A$ and $B$ are $ 2\hat{i}+2\hat{j}+\hat{k}$ and $2\hat{i}+4\hat{j}+4\hat{k}$
The length of the internal bisector of $?BOA$ triangle $AOB$ is
Updated On: Sep 1, 2023
- $\sqrt{\frac{136}{9}}$
- $\frac{\sqrt{136}}{9}$
- $\sqrt{\frac{217}{9}}$
- $\frac{20}{3}$
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The Correct Option is A
Solution and Explanation
The correct answer is A:\(\sqrt{\frac{136}{9}}\)
Given that;
Position vector of A & B are;
\(2\hat i +2\hat j+\hat k\) &
\(2\hat i+4\hat j+4\hat k\) respectively
\(\therefore|OA|=\sqrt{2^2+2^2+1^2}=3units\)
\(|OB|=\sqrt{2^2+4^2+4^2}=6units\)
Now let internal bisector OP divides AB with ratio \(1\ratio 2\)
\(\therefore\) Position vector of D is \((2,\frac{8}{3},2)\)
\(\therefore |OD|=\sqrt{2^2+(\frac{8}{3})^2+2^2}\)
\(=\sqrt{\frac{136}{9}}\)
Given that;
Position vector of A & B are;
\(2\hat i +2\hat j+\hat k\) &
\(2\hat i+4\hat j+4\hat k\) respectively
\(\therefore|OA|=\sqrt{2^2+2^2+1^2}=3units\)
\(|OB|=\sqrt{2^2+4^2+4^2}=6units\)
Now let internal bisector OP divides AB with ratio \(1\ratio 2\)
\(\therefore\) Position vector of D is \((2,\frac{8}{3},2)\)
\(\therefore |OD|=\sqrt{2^2+(\frac{8}{3})^2+2^2}\)
\(=\sqrt{\frac{136}{9}}\)
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Concepts Used:
Vector Algebra
A vector is an object which has both magnitudes and direction. It is usually represented by an arrow which shows the direction(→) and its length shows the magnitude. The arrow which indicates the vector has an arrowhead and its opposite end is the tail. It is denoted as
The magnitude of the vector is represented as |V|. Two vectors are said to be equal if they have equal magnitudes and equal direction.
Vector Algebra Operations:
Arithmetic operations such as addition, subtraction, multiplication on vectors. However, in the case of multiplication, vectors have two terminologies, such as dot product and cross product.