Question:
The points of discontinuity of the function \(f\) defined by \(f(x) = \begin{cases} x+2 & x≤1 \\ x-2 &1<x<2\\ 0& x≥2\end{cases}\) are:
The points of discontinuity of the function \(f\) defined by \(f(x) = \begin{cases} x+2 & x≤1 \\ x-2 &1<x<2\\ 0& x≥2\end{cases}\) are:
Updated On: May 21, 2024
- 0 and 1
- 1 and 2
- 1
- 2
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The Correct Option is C
Solution and Explanation
The correct option is (C):1
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