Question

The photograph of a house occupies an area of 1.75 \(\text{cm}^2\) on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 \(\text m^2\). What is the linear magnification of the projector-screen arrangement.

Answer 1

Area of the house on the slide = 1.75 \(\text{cm}^2\)
Area of the image of the house formed on the screen = 1.55 \(\text m^2\) 
= 1.55 × \(10^4\) \(\text{cm}^2\)
Arial magnification, ma =\(\frac{\text{ Area of image }}{\text{ Area of object }}\)= \(\frac{1.55}{1.75} \times 10^4\)
\(\therefore\) Linear magnifications, ml =\(\sqrt{m_a}\) 
=\( \sqrt{ \frac{1.55 }{ 1.75 }× 10^4}\) = 94.11