The area A of a rhombus is given by:
Area = (1/2) × d₁ × d₂
where d₁ and d₂ are the diagonals.
The perimeter of the rhombus is 40 cm, so the length of each side is:
Side length = 40 / 4 = 10 cm
One diagonal is given as d₁ = 16 cm. Since the diagonals bisect each other at right angles, each half-diagonal forms a right-angled triangle with the side of the rhombus.
Applying the Pythagorean theorem:
(d₁ / 2)² + (d₂ / 2)² = Side²
Substituting d₁ = 16 and Side = 10:
(16 / 2)² + (d₂ / 2)² = 10²
8² + (d₂ / 2)² = 100
64 + (d₂ / 2)² = 100
(d₂ / 2)² = 36 ⇒ d₂ / 2 = 6
d₂ = 12 cm
Area = (1/2) × 16 × 12
= 96 sq. cm
Thus, the correct answer is (C) 96 sq. cm.
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$