Question

The particle which is expected to be emitted along with \( Y \) in the following nuclear reaction is \[ { }^{198}_{80}X \rightarrow { }^{197}_{79}Y + ? \]

• A. \( \alpha \)-particle
• B. \( \beta^+ \)-particle
• C. \( \beta^- \)-particle
• D. proton
• E. neutron

Hint:

In nuclear reactions, when the atomic number decreases by 1, the particle emitted is a proton.

Answer 1

The Correct Option is D

In the given nuclear reaction: \[ ^{198}_{80}X \rightarrow ^{197}_{79}Y + ? \] The atomic number decreases by 1, implying the emission of a proton, as a proton carries a positive charge and reduces the atomic number by 1. 
Hence, the correct answer is (D).