Question:

The pair of equations 2x+3y= 5 and 6x+ky = 12 has no solution if k=

Updated On: Apr 25, 2025
  • 3
  • 6
  • 9
  • 12
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The Correct Option is C

Solution and Explanation

To determine the condition for no solution in a pair of linear equations, the condition is: \[ \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \] Given equations are: \[ 2x + 3y = 5 \quad \text{(1)} \\ 6x + ky = 12 \quad \text{(2)} \] Here: \[ a_1 = 2,\ a_2 = 6,\ b_1 = 3,\ b_2 = k,\ c_1 = 5,\ c_2 = 12 \] Now apply the condition: \[ \frac{a_1}{a_2} = \frac{2}{6} = \frac{1}{3}, \quad \frac{b_1}{b_2} = \frac{3}{k} \] For no solution: \[ \frac{1}{3} = \frac{3}{k} \Rightarrow k = 9 \]

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