For SO₃²⁻ (sulfite ion), The oxidation state of sulfur can be calculated as follows:
Let the oxidation state of sulfur be x. So, you have:
x + 3(-2) = -2
x - 6 = -2
x = +4
For S₂O₄²⁻ (dithionite ion), The oxidation state of sulfur can be calculated as follows:
x + 4(-2) = -2
x - 8 = -2
x = +6
For S₂O₆²⁻ (tetrathionate ion), The oxidation state of sulfur can be calculated as follows:
x + 6(-2) = -2
x - 12 = -2
x = +10
Now, let's order these oxidation states:
+4 (SO₃²⁻) < +6 (S₂O₄²⁻) < +10 (S₂O₆²⁻)
So, the correct option is (A): S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
The steam volatile compounds among the following are:
Choose the correct answer from the options given below:
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
\[ \begin{array}{|c|c|} \hline \textbf{LIST-I (Redox Reaction)} & \textbf{LIST-II (Type of Redox Reaction)} \\ \hline A. \, CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) & I. \, \text{Disproportionation reaction} \\ B. \, 2NaH(s) \rightarrow 2Na(s) + H_2(g) & II. \, \text{Combination reaction} \\ C. \, V_2O_5(s) + 5Ca(s) \rightarrow 2V(s) + 5CaO(s) & III. \, \text{Decomposition reaction} \\ D. \, 2H_2O(aq) \rightarrow 2H_2(g) + O_2(g) & IV. \, \text{Displacement reaction} \\ \hline \end{array} \]
Oxidation number, also called oxidation state, the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.
Oxidation number of an atom is defined as the charge that an atom appears to have on forming ionic bonds with other heteroatoms. An atom having higher electronegativity (even if it forms a covalent bond) is given a negative oxidation state.
The definition, assigns oxidation state to an atom on conditions, that the atom –
Oxidation number is a formalized way of keeping track of oxidation state.
Read More: Oxidation and Reduction
Oxidation number or state of an atom/ion is the number of electrons an atom/ion that the molecule has either gained or lost compared to the neutral atom. Electropositive metal atoms, of group I, 2 and 3 lose a specific number of electrons and have always constant positive oxidation numbers.
In molecules, more electronegative atom gain electrons from a less electronegative atom and have negative oxidation states. The numerical value of the oxidation state is equal to the number of electrons lost or gained.
Oxidation number or oxidation state of an atom or ion in a molecule/ion is assigned by: