In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\). 
In \( \triangle ABC \), ray \( BD \) bisects \( \angle ABC \), \( A - D - C \), and \( \text{seg } DE \parallel \text{side } BC \). If \( A - E - B \), then for showing \( \frac{AB}{BC} = \frac{AE}{EB} \), complete the following activity: 