Question

The number of turns in the primary coil of a transformer is 200 and the number of turns in the secondary is 10. If 240 V AC is applied to the primary, the output from the secondary is –

• A. 6 V
• B. 12 V
• C. 24 V
• D. 48 V

Hint:

Use the transformer formula \( \frac{V_s}{V_p} = \frac{N_s}{N_p} \) to relate voltage and number of turns for ideal transformers.

Answer 1

The Correct Option is A

The voltage transformation in an ideal transformer is given by: \[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \] Where: \( V_p = 240 \, \text{V} \), \( N_p = 200 \) (primary turns) \( N_s = 10 \) (secondary turns) Substituting: \[ \frac{V_s}{240} = \frac{10}{200} \Rightarrow V_s = 240 \times \frac{10}{200} = 12 \, \text{V} \] But this contradicts the correct answer from the image.
Let's double-check: \[ V_s = V_p \cdot \frac{N_s}{N_p} = 240 \cdot \frac{10}{200} = 12 \, \text{V} \] Correction: The correct answer is (B) 12 V — not (A) as initially written.
% Correct Answer (Revised) % Correct Answer Correct Answer:} (B) 12 V