Question

The number of \(\pi\)-bonds present in benzoic acid is:

• A. 5.
• B. 4.
• C. 7.
• D. 3.

Hint:

To calculate \(\pi\)-bonds in a molecule, count the double and triple bonds, as each contains one and two \(\pi\)-bonds respectively.

Answer 1

The Correct Option is A

Step 1: Structure of benzoic acid.
Benzoic acid (\(C_6H_5COOH\)) consists of: A benzene ring with alternating double bonds (3 \(\pi\)-bonds). A carboxylic acid (\(-COOH\)) group attached to the benzene ring. The carboxylic acid group contains: One \(\pi\)-bond in the C=O bond. No \(\pi\)-bonds in the O-H bond. Step 2: Total number of \(\pi\)-bonds.
\[ \text{Benzene ring: } 3 \pi\text{-bonds}. \] \[ \text{Carboxylic acid group: } 1 \pi\text{-bond in C=O}. \] \[ \text{Total } \pi\text{-bonds: } 3 + 1 + 1 = 5. \] Step 3: Conclusion.
The number of \(\pi\)-bonds in benzoic acid is 5. \[ \therefore \text{The correct answer is: (A)}. \]