Question:
The number of permutations of taking all letters and keeping the vowels of the words in the odd places is
The number of permutations of taking all letters and keeping the vowels of the words in the odd places is
Updated On: Jul 7, 2022
- $96$
- $144$
- $512$
- $576$
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The Correct Option is D
Solution and Explanation
Number of odd places $1, 3, 5, 7$ i.e., $4$
Vowels are $O, I, E$
$\therefore$ reqd. number of ways $=\,^{4}P_{3}\times4!=24\times24$
$=576$
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Notes on Permutations
Concepts Used:
Permutations
A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:
\(^nP_r = \frac{n!}{(n-r)!}\)
nPr = permutation
n = total number of objects
r = number of objects selected
Types of Permutation
- Permutation of n different things where repeating is not allowed
- Permutation of n different things where repeating is allowed
- Permutation of similar kinds or duplicate objects