Question:

The number of permutations of 4 letters that can be made out of the letters of the word EXAMINATION is

Updated On: Sep 3, 2024
  • $ 2454 $
  • $ 2452 $
  • $ 2450 $
  • $ 1806 $
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The Correct Option is A

Solution and Explanation

In a word EXAMINATION has $ 2A,\,2I,\,2N,\,E,\,M,\,O,\,T,\,X, $ therfore 7 letters can be chosen in following ways Case I when 2 alike of one kind and 2 alike of second kind of is
$ ^{3}{{C}_{2}} $ .
$ \therefore $ Number of words $ {{=}^{3}}{{C}_{2}}\times \frac{4!}{2!\,\,2!}=18 $
Case II when 2 alike of one kind and 2 different ie,
$ ^{3}{{C}_{1}}{{\times }^{7}}{{C}_{2}}. $
$ \therefore $ Number of words $ {{=}^{3}}{{C}_{1}}{{\times }^{7}}{{C}_{2}}\times \frac{4!}{2!} $
$ =756 $ Case III when all are different. ie, $ ^{8}{{C}_{4}} $ .
$ \therefore $ Number of words $ {{=}^{8}}{{C}_{4}}\times 4!=1680 $
Hence, total number of words $ =18+756+1680 $
$ =2454 $
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Concepts Used:

Permutations

A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:

\(^nP_r = \frac{n!}{(n-r)!}\)

 nPr = permutation

 n = total number of objects

 r = number of objects selected

Types of Permutation

  • Permutation of n different things where repeating is not allowed
  • Permutation of n different things where repeating is allowed
  • Permutation of similar kinds or duplicate objects