To find the number of one-one (injective) functions from a set of 3 elements to a set of 5 elements, we need to assign distinct elements from the range set to the elements in the domain.
Step 1: Total Elements in Domain and Codomain
The domain has 3 elements 1, 2, 3 and the codomain has 5 elements a, b, c, d, e.
Step 2: Assign Values to Each Element
Since we need a one-one function, each element in the domain must map to a distinct element in the codomain.
For the first element in the domain (1), we have 5 choices from the codomain (a, b, c, d, e).
For the second element in the domain (2), since the function is one-one, we have 4 remaining choices.
For the third element in the domain (3), we have 3 remaining choices.
Step 3: Total Number of Functions
To calculate the total number of one-one functions, multiply the number of choices for each element:
\[ \text{Total number of one-one functions} = 5 \times 4 \times 3 = 60 \]
Thus, the correct answer is:
\[ \boxed{60} \]
Let A be the set of 30 students of class XII in a school. Let f : A -> N, N is a set of natural numbers such that function f(x) = Roll Number of student x.
On the basis of the given information, answer the followingIs \( f \) a bijective function?
Five friends A, B, C, D, and E are sitting in a row facing north, but not necessarily in the same order:
B is to the immediate left of C
E is not at any of the ends
D is to the right of E but not next to C
A is at one of the ends
Who is sitting in the middle?