To determine the number of non-bonding electrons present in the frontier molecular orbitals of HF (hydrogen fluoride), we need to understand the molecular orbital theory as applied to diatomic molecules like HF.
In HF, the bond is formed between hydrogen and fluorine. The fluorine atom is more electronegative and therefore attracts the bonding electrons more strongly than hydrogen. Let's consider the electron configuration for each atom:
In the molecular orbital (MO) theory, when HF is formed, the 1s orbital of hydrogen and the 2p orbitals of fluorine overlap to form a bonding molecular orbital and a non-bonding molecular orbital. The 1s2 of fluorine and the 2s2 of fluorine do not participate in bonding and are considered non-bonding electron pairs.
Reviewing the MOs:
Therefore, the non-bonding electrons present in the frontier molecular orbitals of HF are those remaining in the fluorine 2p orbitals that do not participate in bonding. Fluorine's 2p orbitals initially have 5 electrons, 2 of which are used in bonding. Thus, 3 electrons are left as non-bonding. However, considering common practice for molecular frontier orbitals interaction:
Thus, the number of non-bonding electrons present in the frontier molecular orbitals is 4 (as there are two non-bonding pairs on fluorine).
Hence, the correct answer is 4.
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The number of chiral carbon centers in the following molecule is ............... 
A tube fitted with a semipermeable membrane is dipped into 0.001 M NaCl solution at 300 K as shown in the figure. Assume density of the solvent and solution are the same. At equilibrium, the height of the liquid column \( h \) (in cm) is ......... 