Question:

The number of integers between 25 and 125, which are divisible by 6, is

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Use $\frac{last - first}{step} + 1$ to count evenly spaced numbers.
Updated On: Feb 25, 2026
  • 15
  • 14
  • 16
  • 18
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The Correct Option is C

Solution and Explanation

Concept: Count multiples within a range. Explanation: Smallest multiple of 6 greater than 25: \[ 30 \] Largest multiple of 6 less than 125: \[ 120 \] Now count terms in A.P.: \[ 30, 36, 42, \dots, 120 \] \[ n = \frac{120 - 30}{6} + 1 = 15 + 1 = 16 \]
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