Question:
The number of amphoteric oxides from the following is
\(\mathrm{CO_2, GeO_2, SnO_2, PbO_2, CO, GeO, SnO, PbO}\)
The number of amphoteric oxides from the following is
\(\mathrm{CO_2, GeO_2, SnO_2, PbO_2, CO, GeO, SnO, PbO}\)
\(\mathrm{CO_2, GeO_2, SnO_2, PbO_2, CO, GeO, SnO, PbO}\)
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Amphoteric oxides react with both acids and bases. Common examples are oxides of elements near the metalloid region, especially Ge, Sn, and Pb in higher oxidation states.
Updated On: Jun 6, 2025
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The Correct Option is B
Solution and Explanation
Let's classify the oxides one by one:
- \( \mathrm{CO_2} \): Acidic oxide
- \( \mathrm{GeO_2} \): Amphoteric
- \( \mathrm{SnO_2} \): Amphoteric
- \( \mathrm{PbO_2} \): Amphoteric
- \( \mathrm{CO} \): Neutral oxide
- \( \mathrm{GeO} \): Amphoteric
- \( \mathrm{SnO} \): Basic
- \( \mathrm{PbO} \): Basic Amphoteric oxides: \( \mathrm{GeO_2}, \mathrm{SnO_2}, \mathrm{PbO_2}, \mathrm{GeO} \) Number of amphoteric oxides = 4
- \( \mathrm{GeO_2} \): Amphoteric
- \( \mathrm{SnO_2} \): Amphoteric
- \( \mathrm{PbO_2} \): Amphoteric
- \( \mathrm{CO} \): Neutral oxide
- \( \mathrm{GeO} \): Amphoteric
- \( \mathrm{SnO} \): Basic
- \( \mathrm{PbO} \): Basic Amphoteric oxides: \( \mathrm{GeO_2}, \mathrm{SnO_2}, \mathrm{PbO_2}, \mathrm{GeO} \) Number of amphoteric oxides = 4
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