Question:

The number of 5-Sylow subgroups in the symmetric group \( S_5 \) of degree 5 is \( \underline{\hspace{1cm}}\).

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Use the Sylow theorems to find the number of Sylow subgroups in finite groups. The divisibility and congruence conditions are key.
Updated On: Jan 7, 2026
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Correct Answer: 6

Solution and Explanation

The number of Sylow \( p \)-subgroups in a finite group is given by the Sylow theorems. For \( S_5 \), the Sylow 5-subgroups correspond to the prime factor 5. By the Sylow theorems:
- The number of Sylow 5-subgroups must divide \( |S_5| = 5! = 120 \).
- The number must also be congruent to 1 modulo 5.
Thus, the possible values are divisors of 120 that are congruent to 1 modulo 5. The only such divisor is 6. Hence, the number of 5-Sylow subgroups in \( S_5 \) is \( \boxed{6} \).
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