Manning's formula for discharge:
\[
Q = \frac{1}{n} A R^{2/3} S^{1/2}
\]
Where:
- \(n = 0.01\),
- \(S = \frac{1}{2500}\),
- depth = 0.4 m.
For a trapezoidal section with 1:1 side slopes:
\[
A = \text{cross-sectional area} = \frac{b \times h}{2} \text{(adjusting for channel shape)}
\]
Using the given formula, the estimated discharge is \( \boxed{0.19}\ \text{m}^3\text{s}^{-1} \).