Question

The molarity (moles per litre) of 34% (w/v) H\(_2\)O\(_2\) aqueous solution (answer in integer) is _________.

Hint:

To calculate molarity, divide the mass of solute (g) by the product of the molar mass of the solute and the volume of the solution in liters.

Answer 1

Step 1: Formula for Molarity.
Molarity (M) is given by: \[ M = \frac{{mass of solute (g)}}{{molar mass of solute (g/mol)} \times {volume of solution (L)}} \] We are given:
The concentration is 34% (w/v), meaning 34 g of H\(_2\)O\(_2\) per 100 mL of solution.
Molar mass of H\(_2\)O\(_2\) = 34 g/mol.
Step 2: Calculating the molarity.
For 100 mL solution: \[ M = \frac{34 \, {g}}{34 \, {g/mol} \times 0.1 \, {L}} = \frac{34}{3.4} = 10 \] Step 3: Conclusion. Thus, the molarity of the solution is \( \boxed{10} \, {M} \).