The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol−1. What is the dissociation constant of acetic acid? Choose the correct option.
2.50×10−5 mol L−1
1.75×10−4 mol L−1
2.50×10−4 mol L−1
1.75×10−5 mol L−1
To find the dissociation constant (\(K_a\)) of acetic acid, we start by using the relationship between molar conductivity at a given concentration (\(Λ_m\)) and the limiting molar conductivity (\(Λ_m^0\)). Acetic acid is a weak electrolyte, so the expression to calculate the molar conductivity at infinite dilution (\(Λ_m^0\)) is given by:
However, for simplicity, we'll use the known value \(Λ_m^0\) for acetic acid, which is approximately \(390 \text{ S cm}^2 \text{ mol}^{-1}\).
Given data:
Using the formula for the degree of dissociation (\(α\)):
Substitute the values:
The dissociation constant (\(K_a\)) is calculated using the formula:
Substitute the values of \(C\) and \(α\):
Therefore, the dissociation constant of acetic acid is \(1.75 × 10^{-5} \text{ mol L}^{-1}\). This matches the correct option.
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