Step 1: Capillary Rise Formul(A)
The capillary rise in a tube is given by the formula:
\[
h = \frac{2 \gamma \cos \theta}{r \rho g}
\]
Where:
\( h \) = capillary rise
\( \gamma \) = surface tension of the liquid
\( \theta \) = angle of contact
\( r \) = radius of the tube
\( \rho \) = density of the liquid
\( g \) = acceleration due to gravity
Step 2: Rearranging the formula for \( r \).
Since the capillary rise is given as 0.25 cm, we rearrange the formula for radius \( r \) of the tube:
\[
r = \frac{2 \gamma \cos \theta}{h \rho g}
\]
Substituting the values:
\[
\gamma = 0.0075 \, \text{kg(f)/m}, \, \rho = 1000 \, \text{kg/m}^3, \, g = 9.81 \, \text{m/s}^2, \, h = 0.25 \, \text{cm} = 0.0025 \, \text{m}
\]
Step 3: Calculation.
By plugging the values into the formula, the radius \( r \) is calculated to be approximately 1 cm, which corresponds to a diameter of 2 cm.
Step 4: Conclusion.
Therefore, the minimum size of the glass tube is 1 cm, making the correct answer (B).