Given:
- Mean of 31 results = 60 → Total sum:
\[
31 \times 60 = 1860
\]
- Mean of first 16 results = 58 → Total sum:
\[
16 \times 58 = 928
\]
- Mean of last 16 results = 62 → Total sum:
\[
16 \times 62 = 992
\]
Since the 16th result is counted twice in both first and last 16 results, we remove it:
\[
\text{16th result} = 1860 - (928 + 992 - x)
\]
\[
x = 1860 - 1920
\]
\[
x = 60
\]
Thus, the 16th result is 60.