Question:
The mean distance between the two atoms of an HD molecule is \( r \), where H and D denote hydrogen and deuterium, respectively. The mass of the hydrogen atom is \( m_H \). The energy difference between the two lowest lying rotational states of HD in multiples of \(\frac{h^2}{m_H r^2}\) is:
The mean distance between the two atoms of an HD molecule is \( r \), where H and D denote hydrogen and deuterium, respectively. The mass of the hydrogen atom is \( m_H \). The energy difference between the two lowest lying rotational states of HD in multiples of \(\frac{h^2}{m_H r^2}\) is:
Updated On: Oct 12, 2024
- \(\frac{3}{2}\)
- \(\frac{2}{3}\)
- 6
- \(\frac{4}{3}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A) : \(\frac{4}{3}\)
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