Question:

The mean and variance of a Binomial distribution are \(4\) and \(\frac43\) respectively, then the value of \(P(X\geq1)\) is:

Updated On: May 21, 2024

\(\frac{80}{81}\)
\(\frac{63}{64}\)
\(\frac{728}{729}\)
\(\frac{665}{729}\)

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The Correct Option is C

Solution and Explanation

The correct option is (C): \(\frac{728}{729}\)

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