Question:

The major product formed in the following reaction is 

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CF$_3$COOH/H$_2$O acts as a mild acid for hydrolyzing acetals and thioacetals to the corresponding carbonyl compounds.
Updated On: Dec 5, 2025
  • A
  • B
  • C
  • D
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The Correct Option is A

Solution and Explanation

Step 1: Reaction type identification.
The reaction is an **acetal (or thioacetal) hydrolysis** under acidic conditions. CF$_3$COOH/H$_2$O is a mild acidic system that can cleave acetals or thioacetals to the corresponding carbonyl compounds.
Step 2: Mechanism.
The methoxy (–OCH$_3$) and thioether (–S–) substituents form a cyclic dithioacetal protecting group around the carbonyl precursor. Upon treatment with CF$_3$COOH/H$_2$O, this cyclic acetal hydrolyzes, regenerating the **aldehyde**.
Step 3: Product formed.
Therefore, the product is a **carbonyl compound (aldehyde)** having the same carbon skeleton.
Hence, structure (B) is correct, representing the aldehyde after deprotection.
Step 4: Conclusion.
The major product is an aldehyde (Option B) obtained via acid-catalyzed hydrolysis of a cyclic thioacetal.
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