Question:
The magnetic flux linked with a coil of $N$ turns of area of cross section $A$ held with its plane parallel to the field $B$ is
The magnetic flux linked with a coil of $N$ turns of area of cross section $A$ held with its plane parallel to the field $B$ is
Updated On: Jun 6, 2022
- $\frac{NAB}{2}$
- $NAB$
- $\frac{NAB}{4}$
- 0
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The Correct Option is D
Solution and Explanation
$\phi=M B A \cos \theta =M B A \cos 190^{\circ} $
$\phi =-M B A$
$\phi =-M B A$
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter