Question:

The letters of the word MODESTY are written in all possible orders and these words are written out as in a dictionary then the rank of the word MODESTY is

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The words in a dictionary are arranged in an alphabetical manner.

Updated On: Apr 23, 2025
  • 5040
  • 720
  • 1681
  • 2520
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The Correct Option is C

Approach Solution - 1

The words in a dictionary are arranged in an alphabetical manner.

Words starting with D are 6! = 720, start with E are 720. start with MD are 5! = 120 and start with ME are 120. Now the first word that starts with MO is nothing but MODESTY. Hence rank of MODESTY is 1681.


Alternate Approach-1

The number of words starting with D, arranging the other 6 letters = 6! =720

The number of words starting with E = 6! = 720

The number of words starting with M = 6! = 720 but one of these words is MODESTY

The number of words starting with MD = 5! =120

The number of words starting with ME = 5! =120

Now the first-word start with MO is MODESTY. 

Hence, the rank of MODESTY = 720 + 720 + 120 + 120 + 1 =1681

Read More: Permutations and Combinations

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Approach Solution -2

In a dictionary, the words are arranged in alphabetical order at every stage.
Starting with the letter D and arranging the remaining 6 letters, we get 6! = 6×5×4×3×2×1 = 720.
Then, starting with the letter E and arranging the other six letters D, M, O, S, T, Y in different ways, we get 6! = 720
The number of words starting with M are 6! = 720 but one of these words is the word ‘MODESTY’ itself.
Therefore, we first determine the number of words starting with MD, ME, MO
Count of words starting with MD = 5! = 120
Count of words starting with ME = 5! = 120
Now, the initial word that starts with MO is noting but MODESTY.
Therefore, rank of MODESTY is :
= 720 + 720 + 120 + 120 + 1 = 1681.
So, the correct option is (C) : 1681.

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Concepts Used:

Permutations

A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:

\(^nP_r = \frac{n!}{(n-r)!}\)

 nPr = permutation

 n = total number of objects

 r = number of objects selected

Types of Permutation

  • Permutation of n different things where repeating is not allowed
  • Permutation of n different things where repeating is allowed
  • Permutation of similar kinds or duplicate objects