The words in a dictionary are arranged in an alphabetical manner.
The words in a dictionary are arranged in an alphabetical manner.
Words starting with D are 6! = 720, start with E are 720. start with MD are 5! = 120 and start with ME are 120. Now the first word that starts with MO is nothing but MODESTY. Hence rank of MODESTY is 1681.
Alternate Approach-1
The number of words starting with D, arranging the other 6 letters = 6! =720
The number of words starting with E = 6! = 720
The number of words starting with M = 6! = 720 but one of these words is MODESTY
The number of words starting with MD = 5! =120
The number of words starting with ME = 5! =120
Now the first-word start with MO is MODESTY.
Hence, the rank of MODESTY = 720 + 720 + 120 + 120 + 1 =1681
Read More: Permutations and Combinations
In a dictionary, the words are arranged in alphabetical order at every stage.
Starting with the letter D and arranging the remaining 6 letters, we get 6! = 6×5×4×3×2×1 = 720.
Then, starting with the letter E and arranging the other six letters D, M, O, S, T, Y in different ways, we get 6! = 720
The number of words starting with M are 6! = 720 but one of these words is the word ‘MODESTY’ itself.
Therefore, we first determine the number of words starting with MD, ME, MO
Count of words starting with MD = 5! = 120
Count of words starting with ME = 5! = 120
Now, the initial word that starts with MO is noting but MODESTY.
Therefore, rank of MODESTY is :
= 720 + 720 + 120 + 120 + 1 = 1681.
So, the correct option is (C) : 1681.
A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:
\(^nP_r = \frac{n!}{(n-r)!}\)
nPr = permutation
n = total number of objects
r = number of objects selected