Question:
The length of a rectangle is increased to \(\frac{3}{2} \) times of its length and breadth is reduced to \(\frac{1}{3}rd\) of its breadth. What is the change in area?
The length of a rectangle is increased to \(\frac{3}{2} \) times of its length and breadth is reduced to \(\frac{1}{3}rd\) of its breadth. What is the change in area?
Updated On: Jan 30, 2025
- \(\frac{1}{3}\)
- \(\frac{1}{4}\)
- \(\frac{1}{2}\)
- No Change
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The Correct Option is D
Solution and Explanation
Let the length of previous rectangle be L.
Then the length of new rectangle = \(\frac{3}{2}\)L.
Let the breadth of previous rectangle be B.
Then new breadth of rectangle =\(\frac{2}{3}\)B.
Now, previous area of rectangle = LB
and the new area = \(\frac{3}{2}\)L × \(\frac{2}{3}\)B = LB
There would be no any change in area of rectangle
So the correct option is (D)
Then the length of new rectangle = \(\frac{3}{2}\)L.
Let the breadth of previous rectangle be B.
Then new breadth of rectangle =\(\frac{2}{3}\)B.
Now, previous area of rectangle = LB
and the new area = \(\frac{3}{2}\)L × \(\frac{2}{3}\)B = LB
There would be no any change in area of rectangle
So the correct option is (D)
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