Question:

The kinetic energy acquired by a mass m in travelling distance d, starting from rest, under the action of a constant force is directly proportional to

Updated On: May 3, 2024
  • m
  • m$^0$
  • $\sqrt m$
  • 1$\sqrt m$
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The Correct Option is B

Solution and Explanation

$v^2=u^2+2as$ or $v^2-u^2=2as$
or $ \, \, v^2-(0)^2=2 \times \frac{F}{m} \times s $ or $v^2 =\frac{2Fs}{m}$ and
K.E =$\frac{1}{2}mv^2=\frac{1}{2}m \times \frac{2Fs}{m}=Fs.$
Thus K.E. is independent of m or directly proportional to m$^0$.
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